Integrand size = 16, antiderivative size = 35 \[ \int \frac {\sec ^3(x)}{a-a \sin ^2(x)} \, dx=\frac {3 \text {arctanh}(\sin (x))}{8 a}+\frac {3 \sec (x) \tan (x)}{8 a}+\frac {\sec ^3(x) \tan (x)}{4 a} \]
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Time = 0.06 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.188, Rules used = {3254, 3853, 3855} \[ \int \frac {\sec ^3(x)}{a-a \sin ^2(x)} \, dx=\frac {3 \text {arctanh}(\sin (x))}{8 a}+\frac {\tan (x) \sec ^3(x)}{4 a}+\frac {3 \tan (x) \sec (x)}{8 a} \]
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Rule 3254
Rule 3853
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \frac {\int \sec ^5(x) \, dx}{a} \\ & = \frac {\sec ^3(x) \tan (x)}{4 a}+\frac {3 \int \sec ^3(x) \, dx}{4 a} \\ & = \frac {3 \sec (x) \tan (x)}{8 a}+\frac {\sec ^3(x) \tan (x)}{4 a}+\frac {3 \int \sec (x) \, dx}{8 a} \\ & = \frac {3 \text {arctanh}(\sin (x))}{8 a}+\frac {3 \sec (x) \tan (x)}{8 a}+\frac {\sec ^3(x) \tan (x)}{4 a} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.86 \[ \int \frac {\sec ^3(x)}{a-a \sin ^2(x)} \, dx=\frac {\frac {3}{8} \text {arctanh}(\sin (x))+\frac {3}{8} \sec (x) \tan (x)+\frac {1}{4} \sec ^3(x) \tan (x)}{a} \]
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Time = 0.68 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.23
method | result | size |
parallelrisch | \(\frac {3 \ln \left (-\cot \left (x \right )+\csc \left (x \right )+1\right )-3 \ln \left (-\cot \left (x \right )+\csc \left (x \right )-1\right )+3 \sec \left (x \right ) \tan \left (x \right )+2 \tan \left (x \right ) \left (\sec ^{3}\left (x \right )\right )}{8 a}\) | \(43\) |
default | \(\frac {-\frac {1}{16 \left (1+\sin \left (x \right )\right )^{2}}-\frac {3}{16 \left (1+\sin \left (x \right )\right )}+\frac {3 \ln \left (1+\sin \left (x \right )\right )}{16}+\frac {1}{16 \left (\sin \left (x \right )-1\right )^{2}}-\frac {3}{16 \left (\sin \left (x \right )-1\right )}-\frac {3 \ln \left (\sin \left (x \right )-1\right )}{16}}{a}\) | \(52\) |
risch | \(-\frac {i \left (3 \,{\mathrm e}^{7 i x}+11 \,{\mathrm e}^{5 i x}-11 \,{\mathrm e}^{3 i x}-3 \,{\mathrm e}^{i x}\right )}{4 \left ({\mathrm e}^{2 i x}+1\right )^{4} a}-\frac {3 \ln \left ({\mathrm e}^{i x}-i\right )}{8 a}+\frac {3 \ln \left ({\mathrm e}^{i x}+i\right )}{8 a}\) | \(74\) |
norman | \(\frac {\frac {5 \tan \left (\frac {x}{2}\right )}{4 a}+\frac {3 \left (\tan ^{3}\left (\frac {x}{2}\right )\right )}{4 a}+\frac {3 \left (\tan ^{5}\left (\frac {x}{2}\right )\right )}{4 a}+\frac {5 \left (\tan ^{7}\left (\frac {x}{2}\right )\right )}{4 a}}{\left (\tan ^{2}\left (\frac {x}{2}\right )-1\right )^{4}}-\frac {3 \ln \left (\tan \left (\frac {x}{2}\right )-1\right )}{8 a}+\frac {3 \ln \left (\tan \left (\frac {x}{2}\right )+1\right )}{8 a}\) | \(80\) |
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none
Time = 0.29 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.31 \[ \int \frac {\sec ^3(x)}{a-a \sin ^2(x)} \, dx=\frac {3 \, \cos \left (x\right )^{4} \log \left (\sin \left (x\right ) + 1\right ) - 3 \, \cos \left (x\right )^{4} \log \left (-\sin \left (x\right ) + 1\right ) + 2 \, {\left (3 \, \cos \left (x\right )^{2} + 2\right )} \sin \left (x\right )}{16 \, a \cos \left (x\right )^{4}} \]
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\[ \int \frac {\sec ^3(x)}{a-a \sin ^2(x)} \, dx=- \frac {\int \frac {\sec ^{3}{\left (x \right )}}{\sin ^{2}{\left (x \right )} - 1}\, dx}{a} \]
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none
Time = 0.23 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.46 \[ \int \frac {\sec ^3(x)}{a-a \sin ^2(x)} \, dx=-\frac {3 \, \sin \left (x\right )^{3} - 5 \, \sin \left (x\right )}{8 \, {\left (a \sin \left (x\right )^{4} - 2 \, a \sin \left (x\right )^{2} + a\right )}} + \frac {3 \, \log \left (\sin \left (x\right ) + 1\right )}{16 \, a} - \frac {3 \, \log \left (\sin \left (x\right ) - 1\right )}{16 \, a} \]
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Time = 0.31 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.34 \[ \int \frac {\sec ^3(x)}{a-a \sin ^2(x)} \, dx=\frac {3 \, \log \left (\sin \left (x\right ) + 1\right )}{16 \, a} - \frac {3 \, \log \left (-\sin \left (x\right ) + 1\right )}{16 \, a} - \frac {3 \, \sin \left (x\right )^{3} - 5 \, \sin \left (x\right )}{8 \, {\left (\sin \left (x\right )^{2} - 1\right )}^{2} a} \]
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Time = 13.60 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.89 \[ \int \frac {\sec ^3(x)}{a-a \sin ^2(x)} \, dx=\frac {3\,\mathrm {atanh}\left (\sin \left (x\right )\right )}{8\,a}+\frac {3\,\sin \left (x\right )}{8\,a\,{\cos \left (x\right )}^2}+\frac {\sin \left (x\right )}{4\,a\,{\cos \left (x\right )}^4} \]
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